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1. If f(x) = (3x-2)/(2x+3), then f'(x) =

asked
User Xlaudius
by
8.6k points

1 Answer

7 votes

Answer:


f'(x)= (13)/((2x+3)^2)\\

Explanation:


f(x)= (3x-2)/(2x+3) \\


f'(x)=(dy)/(dx) = (d)/(dx)((3x-2)/(2x+3))\\ f'(x)= ((2x+3)(d)/(dx)(3x-2)-(3x-2)(d)/(dx)(2x+3) )/((2x+3)^(2) ) \\f'(x)= ((2x+3)(3)-(3x-2)(2))/((2x+3)^(2) ) \\


f'(x)= (6x+9-6x+4)/((2x+3)^(2) )\\ f'(x)= (13)/((2x+3)^2)\\

answered
User Orluke
by
8.5k points

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