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5 votes
If n=22, ¯x (x-bar)=45, and s=10, find the margin of error at a 95% confidence level (use at least two decimal places)

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User Shorrty
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1 Answer

3 votes
The margin of error (E) can be calculated using the formula:

E = t_(α/2) * (s/√n)

Where t_(α/2) is the critical value of the t-distribution with (n-1) degrees of freedom at the desired level of confidence (α/2), s is the sample standard deviation, and n is the sample size.

At a 95% confidence level, the value of α/2 is 0.025. Using a t-distribution table or calculator with (n-1) = 21 degrees of freedom, we find that the critical value is approximately 2.08.

Substituting the given values into the formula, we get:

E = 2.08 * (10/√22)

E ≈ 4.38

Therefore, the margin of error at a 95% confidence level is approximately 4.38.
answered
User OnengLar
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8.3k points
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