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1 vote
3. Find the equation of a circle with the endpoints of the diameter at (0, 8) and (0,-2)

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User Nesa
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7.9k points

1 Answer

4 votes

Explanation:

remember, the general equation for a circle is

(x - h)² + (y - k)² = r²

r is the radius, (h, k) is the center point of the circle.

the line (0, 8) to (0, -2) is a diameter, so, the center of the circle is the midpoint between both points.

remember, the midpoint between 2 points (x1, y1) and (x2, y2) is

((x1+x2)/2, (y1+y2)/2)

in our case :

((0+0)/2, (8-2)/2) = (0, 3)

the distance from the center point to the endpoint is e.g

(0, 3) to (0,8) = 8-3 = 5.

and that is the radius.

the equation of the circle is therefore :

(x - 0)² + (y - 3)² = 5²

x² + (y - 3)² = 25

answered
User Dukevin
by
8.6k points

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