How many grams of water would be formed from 96.0 g NH3 in a reaction represented by the balanced equation below. 4 NH3(g) + 3 O₂(g) → 2 N₂(g) + 6 H₂O(l)

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asked Feb 19, 2024 130k views

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Diogo Paschoal · Answer 1 · 2024-02-23T06:32:58+0000

Answer:

4 NH3(0) + 3 O2(g) → 2 N2(g) + 6H20() ... How many grams of water would be formed from 96.0 g NH3 in a reaction represented by the balanced equation below.

Missing: 6 ‎H₂O( ‎l)

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How many grams of water would be formed from 96.0 g NH3 in a reaction represented by the balanced equation below. 4 NH3(g) + 3 O₂(g) → 2 N₂(g) + 6 H₂O(l)

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How many grams of water would be formed from 96.0 g NH3 in a reaction represented by the balanced equation below. 4 NH3(g) + 3 O₂(g) → 2 N₂(g) + 6 H₂O(l)​

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How many grams of water would be formed from 96.0 g NH3 in a reaction represented by the balanced equation below. 4 NH3(g) + 3 O₂(g) → 2 N₂(g) + 6 H₂O(l)