Question

300.0 mL of a 0.400 M solution of NaI is diluted to 700.0 mL. What is the new concentration of the solution?

Answer 1

the new concentration of the solution is 0.171 M.

Step-by-step explanation:

To solve this problem, we can use the formula for dilution:

C1V1 = C2V2

where C1 is the initial concentration, V1 is the initial volume, C2 is the final concentration, and V2 is the final volume.

Substituting the given values, we get:

(0.400 M)(300.0 mL) = C2(700.0 mL)

Solving for C2, we get:

C2 = (0.400 M)(300.0 mL) / (700.0 mL)

C2 = 0.171 M

Therefore, the new concentration of the solution is 0.171 M.