Question

suppose that the efficacy of a certain drug is . consider the sampling distribution (sample size ) for the proportion of patients cured by this drug. what is the mean of this distribution? what is the standard error of this distribution? round your answer to three decimal places.

Answer 1

Answer: Assuming that the proportion of patients cured by the drug is p = 0.6 and the sample size is n = 100, we can find the mean and standard error of the sampling distribution as follows:

Mean = p = 0.6

Standard error = sqrt[(p*(1-p))/n] = sqrt[(0.6*(1-0.6))/100] = 0.049

Rounding to three decimal places, the standard error is 0.049.

Explanation: