Question

A solution has a concentration of 3.0 M and a volume of 0.20 L. If the solution is diluted to 4.0 L, what is the new concentration, in molarity?

Your answer should have two significant figures.

Answer 1

Answer:

concentration2 = 0.15 M

Step-by-step explanation:

The number of moles of solute in the original solution can be calculated as:

moles = concentration × volume
moles = 3.0 M × 0.20 L
moles = 0.60 mol

When this solution is diluted to a final volume of 4.0 L, the number of moles of solute remains constant. This can be expressed using the equation:

moles1 = moles2

where moles1 is the initial number of moles and moles2 is the final number of moles.

Thus,

moles1 = moles2
0.60 mol = concentration2 × 4.0 L

Solving for concentration2 gives:

concentration2 = moles2 / volume2
concentration2 = 0.60 mol / 4.0 L
concentration2 = 0.15 M

Therefore, the new concentration of the diluted solution, to two significant figures, is 0.15 M.