Question

What are the solutions to the quadratic equation below?

10x17x+3=0
O A.
x=-
x=-- and x = -1/
5
O B. x=² and x = 1/
X
O C. x=
3
10
15
and x = 1
OD. x=3 and x = 1

Answer 1

The given quadratic equation is: 10x^2 + 7x + 3 = 0.

To solve this quadratic equation, we can use the quadratic formula:

x = (-b ± sqrt(b^2 - 4ac)) / 2a

where a = 10, b = 7, and c = 3.

Substituting these values into the formula, we get:

x = (-7 ± sqrt(7^2 - 4(10)(3))) / 2(10)

x = (-7 ± sqrt(49 - 120)) / 20

x = (-7 ± sqrt(-71)) / 20

Since the square root of a negative number is not a real number, this quadratic equation does not have any real solutions. Therefore, none of the options (A), (B), (C), or (D) are correct.