Answer: This situation involves choosing a group of 5 players out of a total of 12 players, where the order in which the players are chosen does not matter. Therefore, this is an example of a combination problem.
The number of ways to choose a group of 5 players out of 12 is given by the formula for combinations:
n C r = n! / (r! * (n-r)!)
where n is the total number of players, r is the number of players being chosen, and "!" represents the factorial operation.
In this case, we have n = 12 and r = 5, so the number of different choices of starters is:
12 C 5 = 12! / (5! * (12-5)!)
= 792
Therefore, there are 792 different choices of starters that the coach can make from the team of 12 players.
Explanation: