Question

Given that log x = 3, log y=7
PLEASE HELP SOLVE 20 PTsS

Answer 1

log (4x2y) = log(4) + log (×2) + log (y)
= 0.6 + 2*log (x) + log (y) (since log (x2) =
2*log (x))
= 0.6 + 2*3 + 7 (since log (x) = 3 and log (y) =
=13.6
Therefore, log (4x3y) = 13.6.

Answer 2

We can use the properties of logarithms to simplify the expression:

log(4x²y) = log(4) + log(x²) + log(y)
= 0.6 + 2*log(x) + log(y) (since log(x²) = 2*log(x))
= 0.6 + 2*3 + 7 (since log(x) = 3 and log(y) = 7)
= 13.6

Therefore, log(4x²y) ≈ 13.6.