Question

Which function has real zeros at x = 3 and x = 7?f(x) = x2 4x – 21f(x) = x2 – 4x – 21f(x) = x2 – 10x 21f(x) = x2 – 10x – 21

Answer 1

Answer: The function that has real zeros at x = 3 and x = 7 is:

f(x) = (x - 3)(x - 7)

Expanding this function using FOIL (First, Outer, Inner, Last) method:

f(x) = x^2 - 10x + 21

Therefore, the answer is:

f(x) = x^2 - 10x + 21

Explanation: