Question

Which equation could be solved using this application of the quadratic formula?

-3√32-4(1)(24)
2(1)
H=
O A.
O B.
O C.
C.
O D.
x² + 6x + 24 = 3x
3x² + 3x + 24 = 3
x² + 3x - 24 3
-
x² + 3x + 24 = 3

Answer 1

Option A

Explanation:

Solving using quadratic formula:

Use the quadratic formula to determine the coefficient of the quadratic equation.

Option A:

x² + 6x + 24 = 3x

x² + 6x + 24 - 3x = 0

x² + 3x + 24 = 0

Compare with ax² + bx + c = 0,

a = 1 ; b = 3 and c = 24

`\boxed{\bf x= (-b \± √(b^2-4ac))/(2a)}`

`= (-3 \±√(3^2-4(1)(24)))/(2(1))`

This equation could be solved using the application of the quadratic formula.

Option B:

3x² + 3x + 24 = 3

3x² + 3x + 24 - 3 = 0

3x² + 3x + 21 = 0

a = 3 ; b = 3 and c = 21

Here, co-efficients are different.

Option C:

x² + 3x - 24 = 3

x² + 3x - 24 - 3= 0

x² + 3x - 27 = 0

a = 1 ; b = 3 and c = -27

Here, co-efficients are different.

Option C:

x² + 3x + 24 = 3

x² + 3x + 24 - 3 = 0

x² + 3x + 21 = 0

a= 1 ; b = 3 and c = 21

Here, co-efficients are different.