Answer:
(-1, -8) is:(x + 7)^2 + (y + 4)^2 = 52
Explanation:
i literally just learned this today so here we go:
The equation of a circle with center (h, k) and radius r is given by:
(x - h)^2 + (y - k)^2 = r^2
We are given the center of the circle as (-7, -4), so we can substitute these values for h and k:
(x - (-7))^2 + (y - (-4))^2 = r^2
(x + 7)^2 + (y + 4)^2 = r^2
We also know that the circle contains the point (-1, -8).
We can substitute these values for x and y, and solve for r:
(-1 + 7)^2 + (-8 + 4)^2 = r^2
36 + 16 = r^2
r^2 = 52
Substituting this value of r^2 into the equation for the circle, we get:
(x + 7)^2 + (y + 4)^2 = 52
Therefore, the equation of the circle with center (-7, -4) containing the point (-1, -8) is:(x + 7)^2 + (y + 4)^2 = 52