Question

The length of a rectangular poster is 2 more inches than two times its width. The area of the poster is 84 square inches. Solve for the dimensions (length and width) of the poster.

Answer 1

Explanation:

w = width

2w + 2 = Length

Area = W x L = 84 = w (2w+2)

84 = 2w^2 + 2w

0 = 2w^2 + 2w - 84 Use Quadratic Formula

a = 2 b=2 c = -84

to find

W = 6 then L = 14 inches