Question

A gun of mass 1.3 kg fires a bullet of mass .007 kg and recoils with a speed of .75 m/s. How fast did the bullet leave the gun?

Answer 1

Step-by-step explanation:

Using conservation of momentum

Momentum before = momentum after

0 = 1.3 kg (.75 m/s) + .007 * v where v = bullet velocity

v = - 139.3 m/s = bullet velocity

(the - means in opposite direction of rifle recoil)

the absolute magnitude is 139.3 m/s