Question

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Answer 1

Period, T
`\Longrightarrow T=(60)/(14) \Longrightarrow T \approx 4.286 \ s`

Using the equation,
`T=2 \pi \sqrt{(l)/(g) }`, find l. ("g" is the acceleration from gravity, 9.8 m/s^2)

`T=2 \pi \sqrt{(l)/(g) } \Longrightarrow 4.286=2 \pi \sqrt{(l)/(9.8) } \Longrightarrow (4.286)/(2 \pi) =\sqrt{(l)/(9.8) }`

`\Longrightarrow ((4.286)/(2 \pi))^2 =(l)/(9.8) \Longrightarrow l =9.8((4.286)/(2 \pi))^2 \Longrightarrow l \approx 4.560 \ m`

Thus, the radio booth is 4.560 m from the field.