Question

Zero(s) where the graph crosses the -axis for f(x)=(x+3)(x+2)(x-1)

Answer 1

Explanation:

Graph crosses x-axis when y=0 (that is f(x)=0).

`(x+3)(x+2)(x-1)=0 \text{ when:}`

`x+3=0\text{ or }x+2=0\text{ or }x-1=0`

`\text{So }x=-3,-2,1`

SOLUTION: Graph crosses x-axis at
`x=-3,-2,1`.