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A collection of nickels, dimes, and quarters consist of 100 coins with a total of $10.25. If there are 3 times as many dimes as quarters, find the number of each type of coins.

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User Sarmad
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7.0k points

1 Answer

5 votes

Answer:

40 nickels

45 dimes

15 quarters

Explanation:

Let's use the following variables to represent the number of each type of coin:

N = number of nickels

D = number of dimes

Q = number of quarters

We know that:

- N + D + Q = 100 (because there are a total of 100 coins)

- 0.05N + 0.10D + 0.25Q = 10.25 (because the total value of the coins is $10.25)

- D = 3Q (because there are three times as many dimes as quarters)

Now we can substitute the third equation into the first two equations to get:

N + 4Q = 100 (equation 1, obtained by substituting D = 3Q)

5N + 10D + 25Q = 1025 (equation 2, obtained by substituting D = 3Q and simplifying)

We can simplify equation 1 by multiplying both sides by 5:

5N + 20Q = 500

Now we can subtract this equation from equation 2 to eliminate N:

10D + 5Q = 525

Next, we can substitute D = 3Q into this equation to get:

10(3Q) + 5Q = 525

Simplifying:

35Q = 525Q = 15

So there are 15 quarters.

We can use D = 3Q to find that there are 45 dimes.

Finally, we can use N + 4Q = 100 to find that there are 40 nickels.

Therefore, there are 40 nickels, 45 dimes, and 15 quarters.

answered
User Adirael
by
8.5k points

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