Question

Find the value of x. (trigonometry)​

Answer 1

Check the picture below.

`\tan(56^o )=\cfrac{\stackrel{opposite}{10}}{\underset{adjacent}{w}}\implies w=\cfrac{10}{\tan(56^o )} \\\\[-0.35em] ~\dotfill\\\\ \tan(34^o )=\cfrac{\stackrel{opposite}{10}}{\underset{adjacent}{w+x}}\implies w+x=\cfrac{10}{\tan(34^o )} \implies x=\cfrac{10}{\tan(34^o )}-w \\\\\\ x=\cfrac{10}{\tan(34^o )}-\cfrac{10}{\tan(56^o )}\implies x\approx 8.1`

Make sure your calculator is in Degree mode.