Question

The equation of a circle is given below

(x - 2/3)^2 +y^2=36
what is the center?
what is the radius?

Answer 1

r = 6

`Center \left((2)/(3),0\right)`

Explanation:

General equation of circle,

`\boxed{\bf (x - h)^2 + (y - k)^2 = r^2}\\\\`

Here, (h , k) is the center and r is the radius.

`(x - (2)/(3))^2 + y^2 = 36\\\\(x - (2)/(3))^2 + (y - 0)^2 = 6^2`

Comparing with general equation,

`Center \left((2)/(3),0\right)`

and r = 6