How many atoms of Kr (Krypton) are in a balloon that contains 2.00 mol of Kr? (4)

Question

asked Dec 16, 2022 228k views

1 Answer

Mvlupan · Answer 1 · 2022-12-22T02:02:20+0000

Answer:

atoms= 1.204x10^(24)atoms

Step-by-step explanation:

Hello!

In this case, according to the Avogadro's number, it is possible to compute the atoms of Kr in 2.00 moles as shown below:

$atoms=2.00mol*(6.022x10^(23)atoms)/(1mol) \\\\atoms= 1.204x10^(24)atoms$

Best regards!