Question

Determine between which consecutive integers the real zeros of f(x)=x²-4x-2 are located.

a. between 3&4 and -1&0
c. between 4&5 and -1&0
b.
between 4&5 and 0&1
d.
between 3&4 and 0&1
Please select the best answer from the choices provided
ΟΑ
OB
Ос
OD

Answer 1

Explanation:

To find the real zeros of f(x) = x²-4x-2, we can use the quadratic formula:

x = (-b ± √(b²-4ac)) / 2a

Here, a = 1, b = -4, and c = -2.

x = (4 ± √(16+8)) / 2

x = (4 ± 2√6) / 2

x = 2 ± √6

Therefore, the real zeros are located between 2-√6 and 2+√6, which is approximately between 0.17 and 3.83.

So, the answer is (d) between 3&4 and 0&1.