What is the Emirical formula of 69.25% gallium and 30.75% phosphorus?

Question

asked Sep 28, 2024 102k views

2 Answers

Harsh Wardhan · Answer 1 · 2024-10-02T09:49:24+0000

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As per question, we are given -

$\:\:\:\:\:\:\longrightarrow \sf \underline{Mass \:of \:Ga = 69.25}$

$\:\:\:\:\:\:\longrightarrow \sf \underline{Mass \:of\: P = 30.75}\\$

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$\longrightarrow \sf No\:of \:moles, n= (Given\: Weight )/(Molar\: mass)\\$

$\:\:\:\:\:\:\:\:\:\:\:\:\longrightarrow \sf Ga_(n) = (69.25)/(69.73)\\$

$\:\:\:\:\:\:\:\:\:\:\:\:\longrightarrow \sf Ga_(n) = 0.9931.......\\$

$\:\:\:\:\:\:\:\:\:\:\:\:\longrightarrow \sf \underline{Ga_(n) = 0.993}\\$

$\longrightarrow \sf No\:of \:moles, n= (Given\: Weight )/(Molar\: mass)\\$

$\:\:\:\:\:\:\:\:\:\:\:\:\longrightarrow \sf P_(n) = (30.75)/(30.97)\\$

$\:\:\:\:\:\: \:\:\:\:\:\:\longrightarrow \sf P_(n) = 0.9928…....\\$

$\:\:\:\:\:\:\:\:\:\:\:\:\longrightarrow \sf \underline{P_(n) = 0.993}\\$

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Divide the number of moles of each element by the least number of moles to get the subscripts of each element.Since the smallest number of moles is 0.993 mol, we divide each number of moles by 0.993 mol.

$\:\:\:\:\:\:\longrightarrow \sf x = (0.993)/(0.993) = 1\\$

$\:\:\:\:\:\:\longrightarrow \sf y= (0.993)/(0.993) = 1\\$

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