Question

after a lemon is squeezed into a bottle of water, the new concentration of H3O is 0.00006M. what is the pH of the water lemon mixture?​

Answer 1

Assuming that the lemon juice is the only source of H3O+ ions in the water, we can use the formula for pH to calculate the pH of the water-lemon mixture:

pH = -log[H3O+]

First, we need to determine the concentration of H3O+ in the solution. We are given that the concentration of H3O+ after the lemon is squeezed into the water is 0.00006 M. Therefore:

[H3O+] = 0.00006 M

Now, we can substitute this value into the pH formula:

pH = -log(0.00006)

pH = 4.22

Therefore, the pH of the water-lemon mixture is 4.22.