Question

50.0 mLs of HCl of unknown concentration is titrated to neutrality with 90.0 mL of 0.650 M NaOH. Calculate the molarity of the HCl.

Answer 1

the molarity of the HCl is 1.17 M.

Step-by-step explanation:

The balanced chemical equation for the reaction between HCl and NaOH is:

HCl + NaOH -> NaCl + H2O

From the equation, we can see that one mole of HCl reacts with one mole of NaOH to produce one mole of NaCl and one mole of water.

First, let's calculate the number of moles of NaOH used:

moles of NaOH = Molarity x Volume in liters

moles of NaOH = 0.650 M x 0.0900 L

moles of NaOH = 0.0585 mol

Since the reaction between HCl and NaOH is a 1:1 stoichiometry, the number of moles of HCl is also equal to 0.0585 mol.

Now, we can use the number of moles of HCl and the volume of HCl to calculate the molarity:

Molarity of HCl = moles of HCl / Volume in liters

Molarity of HCl = 0.0585 mol / 0.0500 L

Molarity of HCl = 1.17 M

Therefore, the molarity of the HCl is 1.17 M.