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four bad apples are mixed accidentally with 20 good apples . obtain the probability distribution of the number of bad apples in a draw of 2 apples at random​

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User Xirehat
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Explanation:

We can solve this problem using the hypergeometric distribution.

The total number of apples is 24 (4 bad + 20 good). Let X be the number of bad apples in a draw of 2 apples.

The probability of drawing 0 bad apples is:

P(X=0) = (20 choose 2) / (24 choose 2) = 190 / 276

The probability of drawing 1 bad apple is:

P(X=1) = ((4 choose 1) * (20 choose 1)) / (24 choose 2) = 64 / 276

The probability of drawing 2 bad apples is:

P(X=2) = (4 choose 2) / (24 choose 2) = 1 / 276

Therefore, the probability distribution of the number of bad apples in a draw of 2 apples at random is:

X | 0 | 1 | 2

----|------|------|-----

P(X) |190/276|64/276|1/276

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User Jtheis
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