Question

10 years ago, a father is 8 times the age of his son. If the total of their ages now is 56, what are their present ages?

Answer 1

Answer: present age of father=42

present age of son=14

Explanation:

let x=present age of father

56-x=present age of son

10 yrs ago:

x-10=age of father

56-x-10=46-x=age of son
age of father=8 times age of son

x-10=8(46-x)

x-10=368-8x

9x=378

x=42

56-x=14

present age of father=42

present age of son=14