Answer: Let's assume that the width of the rectangular room is "x" meters. Then, according to the problem, the length of the room is 2 times the width, which means the length is "2x" meters.
The perimeter of the room is the sum of all four sides, so we can write:
Perimeter = 2 × (length + width)
Substituting the values, we get:
48 = 2 × (2x + x)
Simplifying the expression, we get:
48 = 2 × 3x
Dividing both sides by 2, we get:
24 = 3x
Solving for "x", we get:
x = 8
Therefore, the width of the room is 8 meters and the length is 2 times the width, which is 2 × 8 = 16 meters.
So the dimensions of the room are 8 meters by 16 meters.
Explanation: