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Let ²-13x - 30 = (x+p) (x+q). If the absolute value of p is greater than the absolute

value of q, which number, p or q, is a negative integer? Explain your answer.

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Answer: We can use the fact that the sum and product of the roots of a quadratic equation are related to its coefficients, and use this relationship to find the values of p and q.

Given the equation ²-13x - 30 = (x+p)(x+q), we can see that the coefficient of the x^2 term is 1, the coefficient of the x term is -13, and the constant term is -30.

By comparing the coefficients with the formula for the sum and product of the roots of a quadratic equation, we have:

p + q = -(-13)/1 = 13

p*q = -30/1 = -30

Since the absolute value of p is greater than the absolute value of q, we know that either p is positive and q is negative, or p and q are both negative. We can eliminate the possibility of p being positive and q being negative, since their product would be negative, and we know that p*q = -30. Therefore, both p and q must be negative integers.

We also know that the sum of p and q is 13, which means that the absolute value of q is less than the absolute value of p. Since p and q are both negative, this means that q has a larger absolute value (i.e., is farther from zero) than p. Therefore, q is the negative integer in this case.

Explanation:

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User Sunil P
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