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Determine if each ordered pair is a solution of the system of equations given

3x+5y=13
x-2y=-3

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Answer:

x = 1 and y = 2 so if in (x, y) form then (1, 2) and if in (y, x) form then (2, 1)

Explanation:

We can solve the system of equations using substitution. We can first isolate x in the second equation. Then, we can plug in the resulting equation for x in the first equation to solve for y:


x-2y=-3\\x=2y-3\\\\3(2y-3)+5y=13\\6y-9+5y=13\\11y-9=13\\11y=22\\y=2

Now, we can plug in 2 for y in either equation to find x:


x-2(2)=-3\\x-4=-3\\x=1

Thus, the solution set is (1, 2) when in the (x, y) form, but it is (2, 1) when in the (y, x) form

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