Question

2. (a) Arnold walked a distance of 50km due north. He continued to move 25km due east.

Sketch a diagram to illustrate the Arnold's movement from the starting point.
Find correct to the nearest whole number the distance between where he started the
journey and where he ended the journey
The bearing of his starting point from his end point.

Answer 1

Explanation:

The sketch is a right-angled triangle.

We can use Pythagoras' theorem.

`z^(2) =x^(2) +y^(2)`

z=√(50^2+25^2)

z= 25√5

z=25*2.23

z=55.75

z≈56km

the distance between where he started the

journey=56km

tan(90-Θ)=25/50

cotΘ=1/2

tanΘ=2

Θ=
`tan^(-1) (2)`

bearing of his starting point from his end point
`tan^(-1) (2)`