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What must be the normal force acting on a crate as it slides across a horizontal floor if the friction acting on the box is 0.490N and the coefficient of friction is 0.250?

What must be the normal force acting on a crate as it slides across a horizontal floor if the friction acting on the box is 0.490N and the coefficient of friction is 0.250?
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What must be the normal force acting on a crate as it slides across a horizontal floor if the friction acting on the box is 0.490N and the coefficient of friction is 0.250?

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User Shachilies
by
8.3k points

1 Answer

0 votes

Answer:

F=0.1225N

Step-by-step explanation:

μ=F/R

0.250=F/0.490

F=0.1225N

answered
User Patto
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7.6k points
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