Question

How many grams of NaCl are needed to make 0.4L of a 1.5 M solution

Answer 1

m = 35.1 g

Step-by-step explanation:

Molarity = number of moles ÷ volume (in litres)

M = n ÷ V

But n = mass ÷ Molar mass

=> M = m ÷ (MM × V)

=> m = M × MM × V

=> m = 1.5 M × (23 + 35.5) g/mol × 0.4 L

=> m = 35.1 g