Answer:
Explanation:
Let H be the sequence given by:
H = {2.5, 7.5, 22.5, 67.5, 202.5, ...}
To define the sequence recursively using function notation, we can use the formula for the nth term of the sequence, based on the previous term:
H(1) = 2.5 (given)
H(n) = 3H(n-1) + 2, for n > 1
This means that to find any term in the sequence after the first term, we multiply the previous term by 3 and add 2.
Using the recursive formula, we can find the next few terms of the sequence:
H(2) = 3H(1) + 2 = 3(2.5) + 2 = 10
H(3) = 3H(2) + 2 = 3(10) + 2 = 32
H(4) = 3H(3) + 2 = 3(32) + 2 = 98
H(5) = 3H(4) + 2 = 3(98) + 2 = 296
So the sequence defined recursively using function notation is:
H(1) = 2.5
H(n) = 3H(n-1) + 2, for n > 1
where H(n) is the nth term of the sequence.