Question

The hypotenuse of a triangle is 13 and one of the legs is 8. What is the length of the other leg of the triangle?round to the nearest 10th

Answer 1

10.2

Explanation:

the hypotenuse is 13 and one of its lengths is 8. Let's assume that the perpendicular is 8 and we have to find the base so

`a^(2)`+
`b^(2)`=
`c^(2)`

8^2+b^2=13^2

64+b^2=169

b^2=169-64

b^2=105

`\sqrt{b^(2)`=
`√(105)`

b=10.246950766

to the nearest tenth

b=10.2