Question

There are 10 males and 18 females in the Data Management class. How many different committees of 5

students can be formed if there must be at least 2 males?

Answer 1

There are 10 males and 18 females in the Data Management class. To form a committee of 5 students with at least 2 males, we can use the combination formula. The number of ways to choose k items from a set of n items is given by the formula nCk = n! / (k! * (n-k)!).

The number of ways to choose 2 males and 3 females is (10C2) * (18C3) = 45,360.

The number of ways to choose 3 males and 2 females is (10C3) * (18C2) = 81,680.

Therefore, there are a total of 45,360 + 81,680 = 127,040 different committees of 5 students that can be formed if there must be at least 2 males.