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What is the complete solution set of l2x-4l=8

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User Mawimawi
by
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1 Answer

6 votes

Answer:


l = (lx_(2)-8)/(4)


l_(2) = x4(l+2) , x\\eq 0, where l =-2 and x =0​

Explanation:


l = (lx_(2)-8)/(4)

l2x−4l=8 Subtract l2x from both sides. −4l=8−l2x The equation is in standard form. −4l=8−xl 2 ​ Divide both sides by −4. −Dividing by −4 undoes the multiplication by −4.


l_(2) = x4(l+2) , x\\eq 0, where l =-2 and x =0​

answered
User Nova Entropy
by
8.0k points

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