Answer:
NaOH is a strong base and when it is dissolved in water, it ionizes completely to form sodium ions (Na+) and hydroxide ions (OH-).
The balanced chemical equation for the reaction of NaOH in water is:
NaOH → Na+ + OH-
In this case, the initial concentration of NaOH is 4.36x10^-13 M.
To find the pH of the solution, we need to first calculate the concentration of hydroxide ions (OH-) in the solution. Since NaOH dissociates completely, the concentration of OH- ions is equal to the initial concentration of NaOH.
[OH-] = 4.36x10^-13 M
Now we can use the following equation to find the pH:
pH = 14 - pOH
Since [OH-] = 4.36x10^-13 M, we can calculate the pOH as follows:
pOH = -log[OH-] = -log(4.36x10^-13) = 12.36
Therefore, the pH of the 4.36x10^-13 M NaOH solution is:
pH = 14 - pOH = 14 - 12.36 = 1.64
The pH of this solution is less than 7, so it is acidic. However, it should be noted that the solution is very weakly acidic due to the extremely low concentration of hydroxide ions.