Question

Answer all parts thoroughly ​

Answer 1

B) She loses 150

C) Her profit per 50 meals= 2650

Explanation:

B) If she caters no meals, X(number of meals she caters)=0

Substitute X=0 into the equation

⇒P=0-0-150 = -150

Since P is negative, She lost 150

C) X= 50

Substitute for x= 50

⇒ P = 2 (
`50^(2)`)- 44(50)-150

P=5000-2200-150

P= 2650

Her profit per catering 50 meals is 2650