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The length of the rectangle below is (2x - 1) cm and its width is (x + 3) cm.

(i) Write an expression in the form ax^2 + bx + c for the area of the rectangle.

(ii) Given that the area of the rectangle is 294 cm2?, determine the value of x.

(iii) Hence, state the dimensions of the rectangle, in centimetres.​

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User Keltia
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1 Answer

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Answer:

(i) The area of a rectangle is given by the product of its length and width. So, the expression for the area of the given rectangle is:

Area = length × width

Area = (2x - 1)(x + 3)

Area = 2x^2 + 5x - 3

Therefore, the expression for the area of the rectangle in the form of ax^2 + bx + c is 2x^2 + 5x - 3.

(ii) We are given that the area of the rectangle is 294 cm^2. So, we can set the expression for the area equal to 294 and solve for x:

2x^2 + 5x - 3 = 294

2x^2 + 5x - 297 = 0

We can then use the quadratic formula to solve for x:

x = [-b ± sqrt(b^2 - 4ac)] / 2a

x = [-5 ± sqrt(5^2 - 4(2)(-297))] / 4

x = [-5 ± sqrt(4661)] / 4

x ≈ 11.02 or x ≈ -26.77

We discard the negative value of x since it does not make sense in this context. Therefore, the value of x is approximately 11.02.

(iii) We can use the value of x to find the dimensions of the rectangle. The length of the rectangle is (2x - 1) cm, so:

Length = (2x - 1) cm

Length = (2 × 11.02 - 1) cm

Length = 21.04 cm

The width of the rectangle is (x + 3) cm, so:

Width = (x + 3) cm

Width = (11.02 + 3) cm

Width = 14.02 cm

Therefore, the dimensions of the rectangle are 21.04 cm by 14.02 cm.

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User Eyescream
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