Answer:
3Cu + 8HNO3 → 3Cu(NO3)2 + 2NO + 4H2O
Step-by-step explanation:
In this equation, copper (Cu) reacts with trioxonitrate(V) (HNO3) to produce copper(II) nitrate (Cu(NO3)2), nitrogen monoxide (NO), and water (H2O).
During the reaction, the copper atoms are oxidized by the nitrate ions in nitric acid to form copper(II) ions (Cu2+), while the nitrate ions are reduced to nitrogen monoxide (NO). The water molecules are produced as a byproduct of the reaction.
Overall, the reaction between copper and trioxonitrate(V) is a redox reaction, where oxidation and reduction occur simultaneously. This reaction is commonly used in the laboratory for the preparation of copper(II) nitrate.