Answer:
This is a problem involving Charles's Law, which states that at constant pressure, the volume of a fixed mass of gas is directly proportional to its absolute temperature. The equation is:V1/T1 = V2/T2where V1 and T1 are the initial volume and temperature, respectively, and V2 and T2 are the final volume and temperature, respectively.We can rearrange this equation to solve for T2:T2 = (V2/T1) x T1First, we need to convert the initial temperature to Kelvin:T1 = 35 ºC + 273.15 = 308.15 KNow we can plug in the values and solve for T2:T2 = (750 mL/500 mL) x 308.15 K
T2 = 462.23 KFinally, we convert the temperature back to Celsius:T2 = 462.23 K - 273.15 = 189.08 ºCTherefore, the new temperature of the carbon monoxide gas is approximately 189.08 ºC when the volume is increased to 750mL