Answer: 2.536 M
Explanation: To calculate the molarity of NaOH in the solution, we need to first calculate the number of moles of NaOH present in the solution.
The formula for calculating the number of moles is:
moles = mass / molar mass
The molar mass of NaOH is 40 g/mol (23 g/mol for Na + 16 g/mol for O + 1 g/mol for H). Therefore, the number of moles of NaOH present in the solution is:
moles of NaOH = 36.5 g / 40 g/mol = 0.9125 mol
The volume of the solution is 360 mL, which is equivalent to 0.360 L. Therefore, the molarity of the NaOH solution is:
Molarity = moles / volume = 0.9125 mol / 0.360 L = 2.536 M
Therefore, the molarity of the NaOH solution is 2.536 M.