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If I have 6.00 moles of gas held at a temperature of 93.5 C and in a container with a volume of 41.7 liters, what is the pressure of the gas (ka)?

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User Yagnesh
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1 Answer

5 votes

We can use the ideal gas law to find out the pressure of the gas.

PV = nRT

P = nRT/V

Where P is the pressure in atm, V is the volume in liters, n is the number of moles, R is the ideal gas constant (0.0821 L atm/mol K), and T is the temperature in Kelvin.

We are given-

  • Moles of gas,n = 6
  • Temperature, T = 93.5 C = 366.5K
  • Volume of gas, V= 41.7 L

On substituting the values -

→ P = ( 6 × 0.0821×366.5)/41.7

→ P = 180.54/41.7

→ P =4.33 atm

→ P = 4.33×101.3 KPa

P = 438.629 KPa

Henceforth, the pressure of the gas is 438.629 KPa.

answered
User Sam Liddicott
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7.8k points

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