asked 18.7k views
0 votes
What is the percent of O in

Ca(С2H302)2?
(Ca = 40.08 g/mol, C = 12.01 g/mol,
H= 1.01 g/mol, O = 16.00 g/mol)

asked
User Zerobu
by
8.1k points

1 Answer

2 votes

40.5%

Step-by-step explanation:

Ca×1 = 40

C×4 = 48

H×6 = 6

O×4 = 64

64÷158×100% = 40.5%

answered
User Sashi Kant
by
8.8k points

Related questions

Welcome to Qamnty — a place to ask, share, and grow together. Join our community and get real answers from real people.