Answer: To determine the probability that the student actually has HIV, we can use Bayes' theorem. Let A be the event that the student has HIV, and B be the event that the ELISA test indicates that the student has HIV. We want to find P(A|B), the probability that the student actually has HIV given that the test is positive.
From the problem, we are given:
P(B|A) = 0.975, the probability of a positive test given that the student has HIV.
P(B|A') = 0.074, the probability of a positive test given that the student does not have HIV.
P(A) = 0.002, the probability that a college student has HIV.
We can calculate P(A'), the probability that the student does not have HIV, as:
P(A') = 1 - P(A) = 1 - 0.002 = 0.998
Using Bayes' theorem, we have:
P(A|B) = P(B|A) * P(A) / [P(B|A) * P(A) + P(B|A') * P(A')]
Plugging in the values we have:
P(A|B) = 0.975 * 0.002 / [0.975 * 0.002 + 0.074 * 0.998]
= 0.025 / 0.0984
= 0.254
Therefore, the probability that the student actually has HIV given a positive test result is only about 25.4%.
Regarding the second question, we should be more concerned about a positive test for a rare disease. In this case, the prevalence of HIV is only 0.2%, which means that most people who test positive for HIV actually do not have the disease. On the other hand, for a common disease that affects a large proportion of the population, a positive test result is more likely to be accurate. Therefore, a positive test result for a rare disease is more concerning as it may lead to unnecessary treatment and anxiety for the patient.