Find the least number which when divided by 35, 56 and 91 leaves the same remainder 7 in each case

Question

asked Jan 10, 2024 210k views

1 Answer

Yamilka · Answer 1 · 2024-01-16T13:07:14+0000

Answer: 3647

Explanation:

The smallest number when divided by 35, 56, 91 leaves a remainder of 7 in each case = 3640 + 7 = 3647.