asked 25.1k views
3 votes
Determine the magnitude of the partial charges in HBr given that the bond length is 1.41 angstroms

and the dipole moment is 0.82 debye.

asked
User Choman
by
7.8k points

1 Answer

3 votes

Answer:

The magnitude of the partial charges in HBr is approximately 1.95 × 10^-19 C.

Step-by-step explanation:

The magnitude of the partial charges in a polar covalent bond can be determined using the formula:

μ = q × d

where μ is the dipole moment, q is the magnitude of the partial charges, and d is the bond length.

In this case, the dipole moment of HBr is given as 0.82 debye, which is equivalent to 0.82 × 3.336 × 10^-30 Cm (since 1 debye = 3.336 × 10^-30 Cm). The bond length is given as 1.41 angstroms, which is equivalent to 1.41 × 10^-10 meters.

Plugging these values into the formula, we get:

0.82 × 3.336 × 10^-30 Cm = q × 1.41 × 10^-10 meters

Solving for q, we get:

q = (0.82 × 3.336 × 10^-30 Cm) / (1.41 × 10^-10 meters) ≈ 1.95 × 10^-19 C

Therefore, the magnitude of the partial charges in HBr is approximately 1.95 × 10^-19 C.

answered
User KC Baltz
by
8.3k points
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