Question

g a 0.750 kg hammer is moving horizontally at 9.50 m/s when it strikes a nail and comes to rest after driving it 1.00 cm into a board. (a) calculate the duration of the impact in seconds. .02105 incorrect: your answer is incorrect. s (b) what was the average force in newtons exerted on the nail?

Answer 1

(a) t = 0.02111

(b) F = 337.5 N

Step-by-step explanation:

We can apply work energy theorem to solve this problem,

`0 - (1)/(2)mv^2 = F_(avg).\Delta x`

(change in kinetic energy = Force applied)

substituting the values given in the question,

`- (0.75)/(2)3^2 = F_(avg).0.01`

solving we get,

`F_(avg) = -337.5 \, N`

We have the equation,

`F_(avg) = ma_(avg)`

substituting the value of m and F we get,

`a_(avg) = -450 \, m/s^2`

We can calculate the duration of impact using the kinematical equations,

`v = u + at`

`0 = 9.5 - 450t`

`t = 0.02111` s