Question

Hi guys! I'm struggling to start and answer this question on the syllabus.

help would be much appreciated

thanks in advance.
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Answer 1

• I₁ ≈ 0.1036∠68.75°
• I₂ ≈ 0.1637∠50.31°

Explanation:

You want the solution in polar form of the system of equations ...

• (2+j6)I₁ -j4·I₂ = 0
• j·I₁ +(8-j10)I₂ = 2

The usual solution methods for a system of equations apply. The attached calculator shows the currents to be ...

• I₁ ≈ 0.1036∠68.75°
• I₂ ≈ 0.1637∠50.31°

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Additional comment

For systems of equations in which the coefficients don't lend themselves to elimination or substitution methods, we prefer matrix methods to find a solution. A suitable calculator makes this relatively easy.